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7b^2-15b+2=0
a = 7; b = -15; c = +2;
Δ = b2-4ac
Δ = -152-4·7·2
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-13}{2*7}=\frac{2}{14} =1/7 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+13}{2*7}=\frac{28}{14} =2 $
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